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20 October, 15:22

A circle has the equation x2+y2-14x-18y+105=0.

What is the equation of the circle in standard form, the location of its center, and the length of its radius?

The equation of the circle is (x+7) 2 + (y+9) 2=25; the center is at (-7,-9), and the radius is 5 units.

The equation of the circle is (x+7) 2 + (y+9) 2=89; the center is at (-7,-9), and the radius is 89--√ units.

The equation of the circle is (x-7) 2 + (y-9) 2=415; the center is at (7,9), and the radius is 415---√ units.

The equation of the circle is (x-7) 2 + (y-9) 2=25; the center is at (7,9), and the radius is 5 units.

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  1. 20 October, 18:20
    0
    The answer to your question is the last option

    Equation in standard form = (x - 7) ² + (y - 9) ² = 5²

    Center = (7, 9)

    Radius = 5

    Step-by-step explanation:

    Equation

    x² + y² - 14x - 18y + 105 = 0

    - Grouping property

    (x² - 14x) + (y² - 18y) = - 105

    - Complete perfect square trinomials

    (x² - 14x + 7²) + (y² - 18y + 9²) = - 105 + 49 + 81

    - Factor

    (x - 7) ² + (y - 9) ² = 25

    or (x - 7) ² + (y - 9) ² = 5²

    Center = (7, 9)

    Radius = 5
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