A fair 6-sided die is rolled 10 times (each roll is independent). What is the probability that the rolled die will not show an even number? (That every roll is odd)

Question

Mathematics

Rohan Randolph

1 November, 01:59

A fair 6-sided die is rolled 10 times (each roll is independent). What is the probability that the rolled die will not show an even number? (That every roll is odd)

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Answers (1)

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Desmond · Answer 1

1/1024.

Step-by-step explanation:

There are 3 odd numbers in the numbers from 1 to 6. So:

Probability (one toss is odd) = 3/6 = 1/2.

So the Probability (10 tosses are all odd) = (1/2) ^10

= 1/1024.