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8 May, 22:04

What quadratic equation has - 4 and 2/3 as it's roots

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  1. 8 May, 22:18
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    3x^2 + 10x - 8 = 0.

    Step-by-step explanation:

    In factor form it would be:

    (x + 4) (3x - 2) = 0 (because x + 4 = 0 gives x = - 4 and 3x - 2 = 0 gives x = 2/3);

    Now change to standard form:

    = 3x^2 - 2x + 12x - 8 = 0

    = 3x^2 + 10x - 8 = 0.
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