Ask Question
3 January, 03:10

Ex. 3 Between the years 2000 and 2010, the population of Cleveland, Ohio decreased, on

average, by 1.85% per year. In 2010, the population was 396,800. If the population S (t),

continues to shrink by 1.85% per year:

a) What will the population be in 2020? State the function S (t).

+1
Answers (1)
  1. 3 January, 03:17
    0
    329,211

    S (t) = 396,800 * (1 - 0.0185) ^ (2020-2010)

    Step-by-step explanation:

    Lets start by the population of 2010. It was 396,800. If it decreases at a 1.85%, per year it means that un 2011 it had:

    396,800 * (1 - 0.0185) = 389,459

    If we want that the year 2011 to appear on the equation we can say that

    S (2011) = 396,800 * (1 - 0.0185) ^ (2011-2010) = 389,459

    As 2011-2010 = 1

    For 2012 it will be the population of 2011 reduced again by 0.0185 (or 1.85%):

    S (2011) * (1 - 0.0185) =

    Replacing S (2011):

    S (2011) * (1 - 0.0185) = 396,800 * [ (1 - 0.0185) ^ (2011-2010) ] * (1 - 0.0185)

    S (2012) = 396,800 * (1 - 0.0185) ^ (2012-2010)

    If we keep with this sequence we can establish a general formula:

    S (t) = 396,800 * (1 - 0.0185) ^ (t-2010)

    Now if we want the population of 2020 just replace t=2020

    S (2020) = 396,800 * (1 - 0.0185) ^ (2020-2010)

    S (2020) = 329,211
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Ex. 3 Between the years 2000 and 2010, the population of Cleveland, Ohio decreased, on average, by 1.85% per year. In 2010, the population ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers