A member of the local department of transportation recorded the number of passengers that arrived on flights at the airport based on the month of the year. Some of her data is in the table, where month 1 is January, month 2 is February, and so on.

Month Passengers

1 3,771

2 3,814

5 3,890

7 3,889

10 3,881

If the curve of best fit for the data is y = - 5x2 + 60x + 3,715, which is the best prediction of the number of passengers that arrived on flights in April?

A.

3,875

B.

3,895

C.

3,915

D.

5,823

Question

Mathematics

Leticia

30 December, 04:00

A member of the local department of transportation recorded the number of passengers that arrived on flights at the airport based on the month of the year. Some of her data is in the table, where month 1 is January, month 2 is February, and so on.

Month Passengers

1 3,771

2 3,814

5 3,890

7 3,889

10 3,881

If the curve of best fit for the data is y = - 5x2 + 60x + 3,715, which is the best prediction of the number of passengers that arrived on flights in April?

A.

3,875

B.

3,895

C.

3,915

D.

5,823

+5

Answers (1)

Know the Answer?

Justice Nunez · Answer 1

The correct option is A, 3875 passengers

Step-by-step explanation:

The curve of best fit for the date y=-5x^2+60x+3715

For April which month 4 which means that x is 4

By substituting 4 for x in the equation we can determine y, the number of passengers that arrived on flights at the airport is determined thus.

y=-5*4^2 + (60*4) + 3715

y=-5*16+240+3715

y=-80+240+3715=3875

The number of passengers that arrived by flights in April, month 4 is 3875