Prove this identity using the product-to-sum identity for sine:

sin^2x = (1-cos (2x)) / 2

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Mathematics

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29 March, 04:18

Prove this identity using the product-to-sum identity for sine:

sin^2x = (1-cos (2x)) / 2

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Answers (1)

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Rishi Stuart · Answer 1

sin x * sin x = 1/2 (cos (x-x) - cos (x+x)) = 1/2 (cos (0) - cos (2x))

Step-by-step explanation:

sin² x = sin x * sin x

using the product-to-sum identity for sine

sin x * sin x = 1/2 (cos (x-x) - cos (x+x)) = 1/2 (cos (0) - cos (2x))

cos (0) = 1

sin² x = (1 - cos (2x)) / 2

Prove this identity using the product-to-sum identity for sine:sin^2x = (1-cos (2x)) / 2

Prove this identity using the product-to-sum identity for sine:

sin^2x = (1-cos (2x)) / 2