Ask Question
24 February, 03:37

A certain magical substance that is used to make solid magical spheres costs $800 per cubic foot. The power of a magical sphere depends on its surface area, and a magical sphere can be sold for $30 per square foot of surface area. If you are manufacturing such a sphere, what size should you make them to maximize your profit per sphere?

+1
Answers (1)
  1. 24 February, 06:40
    0
    the sphere should be constructed with a radius R = 0.075 ft in order to maximise the profit

    Step-by-step explanation:

    since the profit function P is

    P = $30/ft² * A - $800/ft³ * V = a*A + b*V

    where A and V are the area and the volume of the sphere respectively. Then

    A = 4*π*R²

    and

    V = 4/3*π*R³

    where R is the radius

    replacing in P

    P = a*A + b*V = 4*π*a * R² - 4/3*π*b*R³ =

    the maximum is found where the derivative of P with respect to R is equal to 0, therefore:

    dP/dR = 8*π*a * R - 4*π*b*R² = 0

    then

    8*π*a * R - 4*π*b*R² = 0

    4*π*R * (2*a - b*R) = 0

    since R>0

    2*a - b*R=0

    R = 2*a/b

    replacing values

    R = 2*a/b = 2*$30/ft² / $800/ft³ = 0.075 ft

    thus the sphere should be constructed with a radius R = 0.075 ft in order to maximise the profit.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A certain magical substance that is used to make solid magical spheres costs $800 per cubic foot. The power of a magical sphere depends on ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers