Ask Question
9 December, 12:52

In a certain college class, 40% of the admitted students were in top 10% of their high school class, 25% were in the next 10%, and the remaining 35% were below the top 20%. Of these students, 90%, 70%, and 20% were passing this course, respectively. If a randomly selected student is failing, then what is the probability that this student was below 20% of his or her high school class (round off to second decimal place) ?

+3
Answers (1)
  1. 9 December, 15:26
    0
    0.71

    Step-by-step explanation:

    The fraction of students failing is the sum of the fractions of students failing in each category. Those fractions are ...

    top 10%: 0.40 * (1 - 0.90) = 0.04

    next 10%: 0.25 * (1 - 0.70) =.075

    bottom 80%: 0.35 * (1 - 0.20) = 0.28

    So, the total fraction of students failing is ...

    0.04 + 0.075 + 0.28 = 0.395

    The desired probability is ...

    p (bottom 80% | failing) = p (bottom 80% & failing) / p (failing)

    = 0.28/0.395 ≈ 0.7089 ≈ 0.71
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “In a certain college class, 40% of the admitted students were in top 10% of their high school class, 25% were in the next 10%, and the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers