Tickets to a play cost $5 at the door and $4 in advance. The theatre club wants to raise at least $400 from the play. Write an inequality for the number of tickets the theatre club needs to sell. If the club sells 40 tickets in advance, how many do they need to sell at the door to reach their goal?

Question

Mathematics

Isla Avila

6 April, 15:02

Tickets to a play cost $5 at the door and $4 in advance. The theatre club wants to raise at least $400 from the play. Write an inequality for the number of tickets the theatre club needs to sell. If the club sells 40 tickets in advance, how many do they need to sell at the door to reach their goal?

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Answers (1)

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Lewis Ali · Answer 1

The number of tickets to sell at the door is 48 tickets.

Step-by-step explanation:

Cost of play at the door = $5 Cost of play in advance = $4 The theater club wants to raise at least $400 from the play. Number of tickets sold in advance = 40 tickets.

Let 'x' be the number of tickets need to sell at the door.

5x + 4 (40) = 400

5x + 160 = 400

5x = 240

x = 240/5

x = 48 tickets

The number of tickets to sell at the door is 48 tickets.