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4 June, 15:14

What is the diameter of a sphere with a volume of 6329/text{ ft}^3,6329 ft

3

, to the nearest tenth of a foot?

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Answers (1)
  1. 4 June, 16:32
    0
    Diameter = 22.9 ft

    Step-by-step explanation:

    We are told that volume of the sphere is 6329 ft³

    Now formula for volume of sphere is given as;

    V = (4/3) πr³

    Thus,

    (4/3) πr³ = 6329

    Multiply both sides by 3/4 to get;

    πr³ = (6329) * 3/4

    πr³ = 4746.75

    Divide both sides by π to obtain;

    r³ = 4746.75/π

    r = ∛ (4746.75/π)

    r = 11.4749 ft

    Now, diameter = 2 x radius

    Diameter = 2 * 11.4749

    Diameter = 22.9498 ft

    Approximating to a tenth of a feet gives;

    Diameter = 22.9 ft
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