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4 April, 18:19

Find z such that the proportion of observations that are less than z in a standard normal distribution is 0.36. (Enter your answer rounded to two decimal places.)

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  1. 4 April, 18:55
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    -0.36

    Step-by-step explanation:

    For any given standard normal distribution, the value of the z-score at the 36th percentile can be found by simple observation of a z-score table.

    At the 36th percentile, a normal distribution has a z-score of roughly - 0.36.

    Therefore - 0.36 is the value of z such that the proportion of observations that are less than z is 0.36.
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