At what value of x does the graph of the following function f (x) have a vertical asymptote? f (x) = 1/x+3

a. 3

b. - 2

c. 0

d. - 3

d

Step-by-step explanation:

The denominator of f (x) cannot be zero as this would make f (x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 ⇒ x = - 3 ← equation of vertical asymptote

The right answer is D