Jess had three more nickels than dimes for a total of $1.50 how many of each coin did he have

N=d+3 because she has 3 more n than d

5n+10d=150

These are givin 5cents in a Nickel so it's 5n

10 cents in a dime so it's 10d

We need her to have 150

Now substitute what we know n to be

Into the equation and solve

5 (d+3) + 10d = 150

5d + 15 + 10d = 150

15d + 15 = 150

15d=135

D=9

Jess had 9 dimes and 12 nickels

9 dimes 12 nickels

Step-by-step explanation:

You can use trial and error method