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30 July, 12:56

Given that tan θ ≈ 1.072, where 0 < θ <, 2 π find the values of sin θ and cos θ.

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  1. 30 July, 15:22
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    The answer to your question is

    sin Ф = 0.731 and sinФ = - 0.731; cos Ф 0.682 and cos Ф = - 0.682

    Step-by-step explanation:

    tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.

    - tan Ф = opposite side / adjacent side

    - 1.072 / 1 = opposite side / adjacent side

    - opposite side = 1.072 and adjacent side = 1

    Calculate hypotenuse

    c² = a² + b²

    c² = 1.072² + 1²

    c² = 2.149

    hypotenuse = c = 1.466

    First quadrangle

    sin Ф = 1.072 / 1.466 = 0.731

    cos Ф = 1 / 1.466 = 0.682

    Third quadrangle

    sin Ф = - 1.072 / 1.466 = - 0.731

    cos Ф = - 1 / 1.466 = - 0.682
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