Which polynomial function f (x) has a leading coefficient of 1, roots - 4, 2, and 9 with multiplicity 1, and root - 5 with multiplicity 3?

f (x) = 3 (x + 5) (x + 4) (x - 2) (x - 9)

f (x) = 3 (x - 5) (x - 4) (x + 2) (x + 9)

f (x) = (x + 5) (x + 5) (x + 5) (x + 4) (x - 2) (x - 9)

f (x) = (x - 5) (x - 5) (x - 5) (x - 4) (x + 2) (x + 9)

Question

Mathematics

Jaylee Becker

3 December, 17:48

Which polynomial function f (x) has a leading coefficient of 1, roots - 4, 2, and 9 with multiplicity 1, and root - 5 with multiplicity 3?

f (x) = 3 (x + 5) (x + 4) (x - 2) (x - 9)

f (x) = 3 (x - 5) (x - 4) (x + 2) (x + 9)

f (x) = (x + 5) (x + 5) (x + 5) (x + 4) (x - 2) (x - 9)

f (x) = (x - 5) (x - 5) (x - 5) (x - 4) (x + 2) (x + 9)

+4

Answers (1)

Know the Answer?

Aurora Chung · Answer 1

"polynomial function f (x) has a leading coefficient of 1"

So because of that, we can eliminate A and B.

Now we have " root - 5 with multiplicity 3 "

That's just product of three factors (x+5)

So D is wrong.

We are left with the only possible correct option C.