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28 August, 02:41

2x - 6 ≥ 6 (x - 2) + 8

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Answers (2)
  1. 28 August, 03:38
    0
    2x - 6 ≥ 6 (x - 2) + 8

    2x - 6 ≥ 6x - 12 + 8

    2x - 6 ≥ 6x - 4

    -6 - 6

    2x ≥ 6x - 10

    -6x - 6x

    -4x ≥ - 10

    x < 2/5
  2. 28 August, 04:03
    0
    2x - 6 > 6 (x - 2) + 8

    use the distrubutive property

    2x - 6 > 6x - 12 + 8

    combine like terms

    2x - 6 > 6x - 4

    get "x" on one side by subtracting 6x from both sides

    -4x - 6 > - 4

    add 6 to both sides so that you have x on one and actual numbers on the other

    -4x > 2

    divide both sides by - 4, and don't forget to flip the sign because you are dividing by a negative!

    x < - 0.5 or x < - 1/2
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