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26 December, 00:47

Find the number of real number solutions for the equation.

X^2-10x+25=0

A: 2

B: Cannot be determined

C: 0

D: 1

+1
Answers (2)
  1. 26 December, 01:57
    0
    Hello here is a solution:

    x²-10x+25 = 0

    x² - 2 (x) (5) + 5² = 0

    puy identity : a²-2ab+b² = (a-b) ²

    (x-5) ² = 0

    x-5 = 0

    the solution is : 5
  2. 26 December, 03:39
    0
    Determinant = b² - 4ac = (-10) ² + 4*1*25 = 100 - 100 = 0

    So it has 1 solution.

    Answer is D
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