Find the number of real number solutions for the equation.

X^2-10x+25=0

A: 2

B: Cannot be determined

C: 0

D: 1

Question

Jay Peck

26 December, 00:47

+1

Answers (2)

Know the Answer?

Scarlett Downs · Answer 1

Hello here is a solution:

x²-10x+25 = 0

x² - 2 (x) (5) + 5² = 0

puy identity : a²-2ab+b² = (a-b) ²

(x-5) ² = 0

x-5 = 0

the solution is : 5

Alfredo Yang · Answer 2

Determinant = b² - 4ac = (-10) ² + 4*1*25 = 100 - 100 = 0

So it has 1 solution.

Answer is D

Find the number of real number solutions for the equation.X^2-10x+25=0A: 2B: Cannot be determinedC: 0D: 1