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30 August, 06:23

In how many ways can a committee of 6 be chosen from 5 teachers and 4 students if the committee must include 3 teachers and 3 students?

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  1. 30 August, 09:35
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    [5! / 3! * 2!] * [4! / 3! * 1!] = (20 / 2) * 4 = 40 ways;
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