The vertices of a right triangle are (-6, 4), (0.0) and (x, 0). Find the value of x.

A. - 4

B. - 6

C. 6

D. 0

Hello here is a solution:

let A (-6; 4) O (0; 0) B (x; 0)

i'have : OA² = OB²+AB² (pytagore theorem)

OA² = (-6-0) ² + (4-0) ² = 36 + 16 = 52

OB² = (x-0) ² + (0-0) ² = x²

AB² = (x+6) ² + (0-4) ² = x²+12x+36 + 16 = x²+12x+52

52 = x² + x²+12x+52

2x² + 12x=0

2x (x+6) = 0

2x=0 or x+6 = 0

x=0 or x = - 6

conclusion : x = - 6

if x = 0 i' have not the triangle