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11 July, 12:25

Let's say that 64% the people on an island are get a rash when they touch a poisonous plant. studies have shown that these people must have at least one copy of a particular dominant allele. what percentage of the population must be heterozygous for this trait if this population conforms to hardy-weinberg expectations for this gene?

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  1. 11 July, 14:24
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    We are given with

    p2 + 2pq = 0.64

    and another formula is

    p2 + 2pq + q2 = 1

    Substituting

    0.64 + q2 = 1

    q2 = 1 - 0.64

    q2 = 0.36

    q = 0.6

    Another formula is

    p + q = 1

    p = 1 - 0.6

    p = 0.4

    What is asked is 2pq

    p2 + 2pq = 0.64

    2pq = 0.64 - 0.4^2

    2pq = 0.48

    There is 48% that has the heterozygous trait.
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