A ball is thrown from a height of 65 meters with an initial downward velocity of 10/ms. The ball's height h (in meters) after t seconds is given by the following. h=65-10t-5t^2 How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth. (If there is more than one answer, list them)

Question

Moran

9 July, 18:59

+5

Answers (1)

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Isaac Solis · Answer 1

So you are asked to find t when the ball hits the ground, so set the equation to 0.

0=65-10t-5t^2