Solve y-2x=3 and 3x-2y=5 using substitution

Y - 2x = 3

3x - 2y = 5

y - 2x = 3

Add 2x to both sides:

y = 2x + 3

Plug in 2x + 3 for 'y' in the 2nd equation:

3x - 2 (2x + 3) = 5

Distribute - 2:

3x - 4x - 6 = 5

Combine like terms:

-x - 6 = 5

Add 6 to both sides:

-x = 11

Multiply - 1 to both sides:

x = - 11

Now plug this into any of the 2 equations to solve for 'y':

y - 2x = 3

y - 2 (-11) = 3

Multiply:

y + 22 = 3

Subtract 22 to both sides:

y = - 19

So the solution is (-11, - 19)