Two candidates attempts to solve a quadratic equation of form / (x^2 px q=0/) one starts with a wrong value of p and find the roots to be 2 and 6 the other starts with a wrong value of q and finds the roots to be 2, - 9 the correct roots are :

Question

Mathematics

Rowan Lyons

25 December, 15:18

Two candidates attempts to solve a quadratic equation of form / (x^2 px q=0/) one starts with a wrong value of p and find the roots to be 2 and 6 the other starts with a wrong value of q and finds the roots to be 2, - 9 the correct roots are :

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Answers (1)

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York · Answer 1

Hello,

Nice like problem.

(x-a) (x-b) = x² - (a+b) x+ab=x²-Sx+P

1) S=8, P=12 value of P is correct

2) S=-7, P=-18, Value of S is correct

x²-7x+12=0

Δ=7²-4*12=1

x = (7-1) / 2 = 3

or x = (7+1) / 2=4

The correct roots are 3 and 4