We toss two dice 1,000 times. How many times do we expect to have the sum of the two dice equal to 4?

Probabltity=desired outcomes/total possible

the ones that sum to 4 are (depends on what die)

1 and 3

3 and 1

2 and 2

2 and 2

4 combinations

how many different possibitlies

6 sides so 6*6 for 2 dice

so 4/36 is porbablity or 1/9

1/9 of all of them so

about 1000/9 times or about 111.1111 times, (rounded to 111 times)