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13 May, 01:05

The length of line segment AK is 640 meters. ∆ABC, ∆CDF, and ∆FJK are similar, and 2AC = CF = 2FK. The first pillar is 20 meters tall. What is the area of ∆CDF

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  1. 13 May, 01:29
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    A to K = 640 meters

    2AC = CF = 2FK

    2AC = 2 (160) = 320

    CF = 320

    2FK = 2 (160) = 320

    AC = 160

    CF = 320

    FK = 160

    AK 640

    BG = 20 m; Area = (160m*20m) / 2 = 3,200/2 = 1,600 m²

    20:160 = x : 320

    20*320 = 160x

    6,400 = 160x

    6,400/160 = x

    40 = x

    Area of CDF = (320m*40m) / 2 = 12,800 / 2 = 6,400 m²
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