Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's bedroom is 1.2 inches wide and 1.6 inches long.

What are the actual measurements of Harper's bedroom?

Enter your answers in the boxes.

Harper's bedroom is c feet wide and c feet long.

Question

Mathematics

Jayla Harvey

9 September, 20:21

Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's bedroom is 1.2 inches wide and 1.6 inches long.

What are the actual measurements of Harper's bedroom?

Enter your answers in the boxes.

Harper's bedroom is c feet wide and c feet long.

+3

Answers (2)

Know the Answer?

Dragonfly · Answer 1

This is problem of ratio and proportion. to solve this, fisrt is calculate the convertion factor.

so the house is 30 feet in actual and 4 in wide on drawing

30 feet / 4 in = 7.5 feet / inso in every inch in the drawing is equivalent to 7.5 feet on actual.

1.2 in (7.5 ft / in) = 9 ft

1.6 in (7.5 ft / in) = 12 ft

Summer Dyer · Answer 2

This is problem of ratio and proportion. to solve this, fisrt is calculate the convertion factor.

so the house is 30 feet in actual and 4 in wide on drawing

30 feet / 4 in = 7.5 feet / inso in every inch in the drawing is equivalent to 7.5 feet on actual.

1.2 in (7.5 ft / in) = 9 ft

1.6 in (7.5 ft / in) = 12 ft