Pedro has a square net in his backyard the diagonal of the net is 6 feet find the length of one side of the net

The answer is 3√2 ft.

We will use the Pythagorean theorem to calculate this. In the right triangle, diagonal, d, is hypotenuse while sides, s, of the net are sides of the triangle:

d² = s² + s²

d² = 2s²

d = 6 ft

6² = 2s²

36 = 2s²

s² = 36/2

s² = 18

s = √18

s = √ (9 * 2)

s = √9 * √2

s = 3√2 ft