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19 July, 04:05

In the equation x^2-6x+8=0 what are the solutions for x

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  1. 19 July, 05:07
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    Hello,

    x²-6x+8=0

    ==>x²-2x-4x+8=0

    ==>x (x-2) - 4 (x-2) = 0

    ==> (x-2) (x-4) = 0

    ==>x=2 or x=4.
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