Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1, y1), (x2, y2)

I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h) 2=4p (y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:

(0-1) ^2=4p (16-20)

Solving for p, p=-1/16.

Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:

(x-1) ^2=4 (-1/16) (0-20)

(x-1) ^2=5

x-1 = (+-) sqrt (5)

x = (+-) sqrt (5) + 1

Here, we have two values of x

x=sqrt (5) + 1 and

x=-sqrt (5) + 1

thus, the answers are: (sqrt (5) + 1,0) and (-sqrt (5) + 1,0).