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30 September, 17:34

Assume y varies inversely with x. If y=9 when x=8 , find the value of y when x=32

When x=32 , y=___

(Type an integer or a decimal)

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  1. 30 September, 21:01
    0
    For inverse variation, y = k/x

    From the given, 9 = k/8

    k = 9 * 8 = 72

    Thus, y = 72/x

    Therefore, when x = 32, y = 72/32 = 2.25

    y = 2.25
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