X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6

The right answer for the question that is being asked and shown above is that:

x = k (1/y)

k = xy

x1y1 = x2y2

8*10 = 6y2

80 = 6y2

y2 = 40/3

So the answer is 40/3

X varies inversely with y and x = 8 when y = 10, what is the value of y when x=6