Find all the values of x for which the function is differentiable.

f (x) = (x^3-8) / (x^2-4x-5)

Question

Mathematics

Damian Johns

31 July, 20:31

Find all the values of x for which the function is differentiable.

f (x) = (x^3-8) / (x^2-4x-5)

+1

Answers (1)

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Walker Villegas · Answer 1

The function is differentiable for:

x² - 4 x - 5 ≠ 0

x² - 5 x + x - 5 ≠ 0

x (x - 5) + (x - 5) ≠ 0

(x - 5) (x + 1) ≠ 0

x ≠ 5 and x ≠ - 1

Answer: x ∈ R / { - 1, 5 }

Find all the values of x for which the function is differentiable.f (x) = (x^3-8) / (x^2-4x-5)

Find all the values of x for which the function is differentiable.

f (x) = (x^3-8) / (x^2-4x-5)