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30 October, 17:40

Find a polynomial function f in standard form with zeros 3i, - 2, 1

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  1. 30 October, 20:23
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    The first thing to remember is that when you have a zero of 3i, you will also have a zero of - 3i. This is because of the way imaginary solutions are created (taking the square root of a negative number). When you take the sqrt you get TWO answers.

    The factors for these zeros are (x - 3i) (x+3i) (x+2) (x-1)

    When you multiply the factors, the polynomial will be:

    x^4 + x^3 + 7x^2 + 9x - 18
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