Given the following sequence, find the 15th term: 3,1,-1,-3,-5

-25 just subtract 2 everytime

3, 1,-1, - 3, - 5

-2 - 2 - 2 - 2

a (n) = a₁ + d (n - 1)

a (n) = 3 - 2 (n - 1)

a (n) = 3 - 2 (n) + 2 (1)

a (n) = 3 - 2n + 2

a (n) = - 2n + 3 + 2

a (n) = - 2n + 5

a (n) = - 2n + 5

a₁₅ = - 2 (15) + 5

a₁₅ = - 30 + 5

a₁₅ = - 25