What is another way to write the expression p⋅ (10-2) p⋅ (10-2) ?

I think you accidentally typed the expression p ⋅ (10 - 2) twice, so I'm going to assume you just meant to type it once.

Anyway, you must use the distributive property multiplying p times 10 and times - 2, separately and adding the results:

p ⋅ (10 - 2)

p (10) + p (-2)

10p - 2p

8p

Solution

P^2 (10-2) ^2