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10 December, 00:45

All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a green followed by a red assuming that the first candy drawn is put back into the packet?

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Answers (2)
  1. 10 December, 01:03
    0
    Probability of drawing a green = 4/13

    Probability of drawing a red = 2/13

    probability of drawing a green and then a red is 4/13 * 2/13 = 6/169
  2. 10 December, 03:45
    0
    Multiply 7 (reds) by 4 (greens) to get 2/13
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