Calculate the discriminant to determine the number of real roots.

Y=x^2-6x+9

How many real roots does the equation have?

A) no real roots

B) no solution to the equation

C) one real root

D) two real roots

Y = x² - 6x + 9

Discriminant = b² - 4ac

Discriminant = (-6) ² - 4 (1) (9)

Discriminant = 36 - 4 (9)

Discriminant = 36 - 36

Discriminant = 0

y = x² - 6x + 9

0 = x² - 6x + 9

0 = x² - 3x - 3x + 9

0 = x (x) - x (3) - 3 (x) - 3 (3)

0 = x (x - 3) - 3 (x - 3)

0 = (x - 3) (x - 3)

0 = (x - 3) ²

0 = x - 3

+ 3 + 3

3 = x

The answer is C.