One of the solutions to x2 - 2x - 15 = 0 is x = - 3. What is the other solution?

x = - 5

x = - 1

x = 1

x = 5

If you factor the equation you can see what the solutions are. Two factor a quadratic of the form ax^2+bx+c, find two values which satisfy two conditions ...

jk=ac=-15 and j+k=b=-2 so j and k must be - 5 and 3 so the factors are:

(x-5) (x+3)

So the other solution is x=5