Any number that is divisible by 3 is also divisible by 6.

Find a counterexample to show that the conjecture is false.

21

18

24

12

21/3 = 7 21/6 = 3.5

18/3 = 6 18/6 = 3

24/3 = 8 24/6 = 4

12/3 = 4 12/6 = 2

Each can be divided to obtain an integer, except:

21/6 = 3.5

So, while 21 can be divided by 3, it cannot be divided by 6 (for an integer anyway)

21/3=7

but

21/6=3.5

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