The sum of 3 numbers is 64. The second number is 3 more than the first. The third number is 11 less than twice the first. Find the numbers

Three numbers can be defined as x, y, and z.

x + y + z = 64

y = x+3

z = 2x - 11

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substitute for y and z

x + (x+3) + (2x-11) = 64

4x - 8 = 64

4x = 72

x = 18

.

y = x+3 = 21

z = 2x - 11 = 2 (18) - 11 = 36-11 = 25

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x + y + z = 18 + 21 + 25 = 64

Correct.

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Answer: The three numbers are 18, 21, and 25.