Select the statements that are true for the graph of y = (x+2) 2+4.

The vertex is (-2, 4) .

The graph has a maximum.

The graph has a minimum.

The vertex is (2, 4).

I think you probably meant (x+2) ^2+4 because the equation you have provided is not written in proper formatting and would actually be a straight line. However, if you meant for that second 2 to be an exponent, you now have a quadratic equation which would graph as a parabola. Remember the basic formula is y = (x-h) ^2 + k where (h, k) is your vertex. So you change the sign of the number in the parenthesis, but not the number outside the parenthesis when finding the vertex. If there is a negative number in front of your equation, then the parabola is flipped upside down so the vertex would be a maximum, but if it is positive, or has nothing in front of it, then the parabola sits up like a bowl so the vertex is a minimum.