A circle is defined by the equation x2 + y2 - x - 2y - 11/4 = 0. What are the coordinates for the center of the circle and the length of the radius?

X2 + y2 - x - 2y - 11/4 = 0

x2 - x + y2-2y-11/4 = 0

we need to elliminate x, y from the equation and get the general form of the circle (x-k) ^2 + (y-h) ^2 = r^2 so,

[ (x-1/2) ^2 - 1/4] + [ (y-1) ^2 - 1] - 11/4 = 0

(x-1/2) ^2 + (y-1) ^2 [ - 1/4 - 1-11/4] = 0

(x-1/2) ^2 + (y-1) ^2 = 4

so the center of the circle is (1/2, 1)

and the rdius is √4 = 2