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4 June, 14:19

The shortest side of a fight triangle measures20 m. The lengths of the other two sides are censecutive odd integers. Find the length of the two aides

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  1. 4 June, 14:25
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    A² + b² = c²

    20² + n² = (n+2) ²

    400 + n² = (n+2) (n+2)

    400 + n²=n² + 2n + 2n + 4

    400 + n² = n² + 4n + 4

    400 + n²-n² = n²-n² + 4n+4

    400 = 4n + 4

    400-4 = 4n + 4-4

    396 = 4n

    396/4 = 4n/4

    n = 99

    20² + 99² = (99+2) ²

    400 + 9801 = 10201

    10201=10201
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