In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglecting to notice that the pipe was one eighth of an inch thick. By what percent did Avery overestimate the carrying capacity of the pipe?

Question

Mathematics

Guest

27 July, 01:28

In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglecting to notice that the pipe was one eighth of an inch thick. By what percent did Avery overestimate the carrying capacity of the pipe?

+1

Answers (1)

Know the Answer?

Anika Beck · Answer 1

Volume of the pipe = πr^2l

Wrong measure = π x (2) ^2 x l = 4πl

Correct measure = π x (2 - 2 (1/8)) ^2 x l = 49/16πl

error = 4πl - 49/16πl = 15/16πl

% error = ((15/16πl) / 49/16πl) x 100% = 30.6%