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6 May, 07:18

A support beam needs to be placed at a 28° angle of elevation so that the top meets a vertical beam 1.6 meters above the horizontal floor. The vertical beam meets the floor at a 90° angle.

Law of sines:

Approximately how far from the vertical beam should the lower end of the support beam be placed along the horizontal floor?

3.0 meters

3.4 meters

3.9 meters

4.4 meters

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Answers (2)
  1. 6 May, 08:08
    0
    The problem states that the law of sines needs to be used but the function tangent can also be used to solve this. Either way, the same answer will be obtained

    Using the law of sines:

    sin 28 / 1.6 = sin (180 - 28 - 90) / x

    where x is the horizontal distance between the ends of the beams

    Solving for x

    x = 3.01 meters

    The answer is

    3.0 meters
  2. 6 May, 08:20
    0
    Approximately the answer is 3.0 meters
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