For a rectangular prism, if the base length was shrunk by a factor of two-thirds, the width was quadrupled, and height was cut in half, how would the changes affect the surface area formula?

The surface area of a rectangular prism is this:

SA = LW + LH + LH

Here are the changes:

L - - > (2/3) L

W - - > 4W

H - - > H/2

So, the new surface area is:

SA' = (2/3) L (4W) + (2/3) L (H/2) + 4W (H/2)

SA' = (8/3) LW + (1/3) LH + 2 WH