What is the integral of y'sinx=ylny ... ?

Y'sinx=ylny, is equivalent to dy / dx (sinx=ylny, and dy sinx=ylny dx

it is similar to dy / ylny = dx/sinx

so integral (dy/ylny = integral dx/sinx)

integral dx/sinx) = Ln{abs value (tan (x / 2 + pi / 4) }

integral (dy/ylny = ln (lny)

final answer is lny = {abs value (tan (x / 2 + pi / 4) }+C, you can find y, or x