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10 June, 03:43

What is the integral of y'sinx=ylny ... ?

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  1. 10 June, 05:56
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    Y'sinx=ylny, is equivalent to dy / dx (sinx=ylny, and dy sinx=ylny dx

    it is similar to dy / ylny = dx/sinx

    so integral (dy/ylny = integral dx/sinx)

    integral dx/sinx) = Ln{abs value (tan (x / 2 + pi / 4) }

    integral (dy/ylny = ln (lny)

    final answer is lny = {abs value (tan (x / 2 + pi / 4) }+C, you can find y, or x
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