Wyatt's eye-level height is 120 ft above sea level, and Shawn's eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = square root of 3h/2, h>0 with d being the distance they can see in miles and h being their eye-level height in feet.

Using the formula given: d = √ (3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:

d = √ (3 (120) / 2)

d = 13.42 miles

For Shawn where h = 270:

d = √ (3 (270) / 2)

d = 20.12 miles

Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.