There are 376 stones in three piles. The second pile has 24 more stones than the first. The third pile has twice as many stones as the second. How many stones in each pile?

Let the stones of each piles be x, y and z respectively.

thus, x + y + z = 376

x=x

y = x + 24

z = 2y = 2 (x+24)

This becomes x + x + 24 + 2 (x+24) = 376

= 4x + 24 + 48 = 376

= 4x + 72 = 376

Thus, 4x = 304

Thus, x = 76

and y = 76 + 24 = 100

and z = 2 x 100 = 200

Thus, first pile has 76 stones, second pile has 100 stones and third pile has 200 stones