Ask Question
28 February, 08:30

Identify the 42nd term of an arithmetic sequence where a1 = - 12 and a27 = 66

+3
Answers (1)
  1. 28 February, 11:50
    0
    A1 = - 12

    a2 = a1+d = - 12+d

    a3 = a2+d = a1+2*d = - 12+2*d

    ...

    a27 = a26+d = a1+26*d = - 12+26*d = 66

    so: 26*d=66+12

    26*d=78

    d=78:26

    d=3

    therefore: a42 = a1+41*d = - 12+41*3 = - 12+123=111
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Identify the 42nd term of an arithmetic sequence where a1 = - 12 and a27 = 66 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers